Recent content by Jarvitä

A normalised vector has length 1. Its components don't necesarrily sum up to 1.

Not enough information here. Assuming the base thrust vector is along the positive z axis, x=r\ sin\,\theta\ cos\,\phi y=r\ sin\,\theta\ sin\,\phi z=r\ cos\,\theta θ being the angle between the z axis and the rz plane (pitch) and φ being the angle between the x axis the the projection of r...

Serbian (native), Russian, German, English, Slovene.

Have you tested it on x86_64 windows XP?

Does not work on 64 bit windows OSes at all.

Пионер (Pioneer) class, with individual ship names like Y.A. Gagarin, Neil Armstrong, etc.

Because, depending on the energy requirements, a (real) reactionless drive potentially implies infinite dV.

And the first thing that comes to mind is the fact that most or quite possibly all people alive today will have long since ceased to exist before having a chance to witness that. :(

OK, I get it, it's "terribly technical", but where is the paper itself? Hard to judge a book by its cover (or a populist press release).

No, but lots of Dragons could. Also, they apparently plan to rely on partial ISRU for life support. http://mars-one.com/mission/technology

Press J again?

Whereas a metric ton is a megagramme, or properly defined as one thousand kilogrammes, since the base SI unit of mass is the kilogramme. Makes more sense to me.

Possibly related? http://www.theregister.co.uk/2012/05/29/rocket_crash_china/

The delta v of a stage is its exaust velocity multiplied by the logarithm of the mass ratio: \Delta v = v_{ex} \times log \frac{m_{fuel}+m_{stage}}{m_{stage}} If you solve for the mass ratio, you get the following relation: \frac{m_{fuel}+m_{stage}}{m_{stage}} = e^{\frac{\Delta v}{v_{ex}}}...

Did you always check the edit history to make sure the article you were looking at wasn't a victim of this?