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semi major axis a = 26552.305 km

eccentricity e = 0.747411

mean anomaly at epoch M_0 = 24.70°

inclination i = 63.96°

longitude of ascending node Ω = 33.79°

argument of periapsis ω = 243.99°

t – t_0 = 4707393.045 sec

Mean anomaly I get from above equation is M = 711.6°

eccentric anomaly E is shown in the textbook.

E = 157.69°

therefore, required mean anomaly should be M = 141.4°

Can someone tell me where I went wrong? I'm not a student, I have no one to ask math questions...

Thanks in advance.