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I'm trying to calculate Mean anomaly which appears in my textbook but I can't get correct answer.
semi major axis a = 26552.305 km
eccentricity e = 0.747411
mean anomaly at epoch M_0 = 24.70°
inclination i = 63.96°
longitude of ascending node Ω = 33.79°
argument of periapsis ω = 243.99°
t – t_0 = 4707393.045 sec
Mean anomaly I get from above equation is M = 711.6°
eccentric anomaly E is shown in the textbook.
E = 157.69°
therefore, required mean anomaly should be M = 141.4°
Can someone tell me where I went wrong? I'm not a student, I have no one to ask math questions...
Thanks in advance.
semi major axis a = 26552.305 km
eccentricity e = 0.747411
mean anomaly at epoch M_0 = 24.70°
inclination i = 63.96°
longitude of ascending node Ω = 33.79°
argument of periapsis ω = 243.99°
t – t_0 = 4707393.045 sec
Mean anomaly I get from above equation is M = 711.6°
eccentric anomaly E is shown in the textbook.
E = 157.69°
therefore, required mean anomaly should be M = 141.4°
Can someone tell me where I went wrong? I'm not a student, I have no one to ask math questions...
Thanks in advance.