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Yes, it sets the orientation of the attach point, so changing it will rotate the booster about the attach point.
And, as you've seen, if the orientation vector isn't normalized, strange results ensue.
Yes, trig is going to be required.
To quote myself, choosing 1 0 0 puts the thing along the X-axis; 0.877 0.5 0 is 30 degrees off from that; 0.5 0.877 0 is 60 degrees off, and so on. To put 8 boosters around, they'd be at 1 0 0, and .707 .707 0, and 0 1 0, and -.707 .707 0, and so on.
And, as you've seen, if the orientation vector isn't normalized, strange results ensue.
Yes, trig is going to be required.
To quote myself, choosing 1 0 0 puts the thing along the X-axis; 0.877 0.5 0 is 30 degrees off from that; 0.5 0.877 0 is 60 degrees off, and so on. To put 8 boosters around, they'd be at 1 0 0, and .707 .707 0, and 0 1 0, and -.707 .707 0, and so on.