Yes, it occured to me this afternoon that when the vessel is in the correct orientation, the roll indicator on the attitude ball would be top centre and they could use that as an indicator of the orbital plane position. Here is a better image of the Apollo FDAI. See how an imaginary line from the centre of the FDAI to the is always tangent to the lines of constant yaw?
BTW, regarding the required orientation of the measurment frame, whilst I could visualise it from your description, I was having a hard time coming up with solid geometrical logic that would prove it for me. Here is what I came up with:
1. For any random target relative velocity vector, it will have one component that has an impact on the relative angular velocity measurements and one component that has no impact. The former will lie in a plane perpendicular to the relative position vector whilst the latter will lie parallel to the relative position vector.
2. The component that lies in the plane perpendicular to the relative position vector can be further broken down in to two components, the in-plane one which is perpendicular to the orbital angular momentum vector, and the out-of-plane one which is perpendicular to in-plane component.
Using cross products to determine the vectors defined by the intersection of the two planes, you get a measurement frame that aligns with the one you described. I hope that my reasoning makes sense.
BTW, regarding the required orientation of the measurment frame, whilst I could visualise it from your description, I was having a hard time coming up with solid geometrical logic that would prove it for me. Here is what I came up with:
1. For any random target relative velocity vector, it will have one component that has an impact on the relative angular velocity measurements and one component that has no impact. The former will lie in a plane perpendicular to the relative position vector whilst the latter will lie parallel to the relative position vector.
2. The component that lies in the plane perpendicular to the relative position vector can be further broken down in to two components, the in-plane one which is perpendicular to the orbital angular momentum vector, and the out-of-plane one which is perpendicular to in-plane component.
Using cross products to determine the vectors defined by the intersection of the two planes, you get a measurement frame that aligns with the one you described. I hope that my reasoning makes sense.